不定积分巩固练习1.2d23xxx________.2.4d1xxx________.3.d4xxx________.4.计算下列不定积分:(1)2sind2cosxxx.(2)2cosd1cosxxx.5.计算22d1xxx.6.计算21d1xxx.7.计算arctanedexxx.8.计算ln1dxx.9.求32d368xxxx.10.求2d11xxxx.11.求arctandxxx.12.求d4e1xx.13.求2arctand1xxxx.14.求4dsincosxxx.15.求arctandxxx.16.求arctan1dxx.17.求2lnsindsinxxx.18.求ede1xxxx.19.求21arcsindxxx.20.求lnd2xxx.1.【解】232233d23d23113dd2344234232323xxxxxxxxxx13ln234423xCx.2.【解】22242dd11arctan1221xxxxCxx.3.【解】22dd22ln442xxxxCxxx.4.【解】(1)222dcossin1cosdarctan2cos222cosxxxxCxx.(2)22coscos111ddcos1d1cos1cos1cosxxxxxxxxx21cossindsincotcscsinxxxxxxxxCx.5.【解】22222211ddd1d111xxxxxxxxxx21arcsinarcsin122xxxxC21arcsin122xxxC.6.【解】221sectanddcscdtansec1txtxtttttxx211lncsccotlnxttCCxx.7.【解】22arctanearctanearctaneddedeexxxxxxttxtt21arctan1arctandd1ttttttt22arctan1arctan1dlnln112ttttttCtttt22arctane1elne21exxxxC.8.【解】令2xt,则222ln1dln1dln1d1txxtttttt21ln11d1ttttt22ln1ln12tttttC1ln12xxxxC.9.【解】令22211368243xxxxxx22433ABCDxxxx,由224323234241AxxBxxCxxxDxx得0108903321266036182481ABCABCDABCDABCD,解得11,,0,122ABCD,故222d111d22243683xxxxxxxx141ln223xCxx.10.【解...