2023高考数学总复习三角恒等变换练习题一、选择题1.,,那么()A.B.C.D.2.函数的最小正周期是()A.B.C.D.3.在△ABC中,,那么△ABC为()A.锐角三角形B.直角三角形C.钝角三角形D.无法判定4.设,,,那么大小关系()A.B.C.D.5.函数是()A.周期为的奇函数B.周期为的偶函数C.周期为的奇函数D.周期为的偶函数6.,那么的值为()A.B.C.D.二、填空题1.求值:_____________.(,0)2x4cos5xx2tan2472477247243sin4cos5yxx522coscossinsinABAB00sin14cos14a00sin16cos16b62c,,abcabcbaccbaacb2sin(2)cos[2()]yxx44222cos2344sincos181318119710000tan20tan403tan20tan402.假设那么.3.函数的最小正周期是___________.4.那么的值为,的值为.5.的三个内角为、、,当为时,取得最大值,且这个最大值为.三、解答题1.求的值.2.假设求的取值范围.3.求值:4.函数(1)求取最大值时相应的的集合;1tan2008,1tan1tan2cos223sincos,223sincos2ABCABCAcos2cos2BCAsinsinsin0,coscoscos0,cos(),22sinsincoscos0010001cos20sin10(tan5tan5)2sin20.,2cos32sinRxxxyyx(2)该函数的图象经过怎样的平移和伸变换可以得到的图象.参考答案一、选择题1.D,2.D3.C为钝角4.D,,5.C,为奇函数,6.B二、填空题1.2.)(sinRxxy(,0)2x24332tan24cos,sin,tan,tan25541tan7xxxxxx25sin()5,21yxTcoscossinsincos()0,cos0,cos0,ABABABCCC02sin59a02sin61b02sin60c22sin2cos2sin42yxxx242T442222221sincos(sincos)2sincos1sin2221111(1cos2)21830000000tan20tan40tan60tan(2040)31tan20tan40000033tan20tan40tan20tan40200811sin21sin2tan2cos2cos2cos2cos2222(cossin)cossin1tan2008cossincossin1tan3.,4.5.当,即时,得三、解答题1.解:.2.解:令,那么3.解:原式()cos23sin22cos(2)3fxxxx22T17,3922417(sincos)1sin,sin,cos212sin223390360,22cos2coscos2sin12sin2sin2222BCAAAAA22132sin2sin12(sin)22222AAA...