第四天答案.pdf-2021-02-27-17-11-26-779.pdfVIP免费

第四天1.【答案】cosa【解析】sinsinlimlimcosxaxaxaxcosaxa洛必达2.【答案】1【解析】1111001lim=lim=1xxxxxxeexee3.【答案】2【解析】211212limlimsincosxxxxxx洛必达4.【答案】2【解析】2002ln(1)lim=lim211cos2xxxxxxx5.【答案】16【解析】322000sinsin1cos1lim=limlim631xxxxxxxxxxxxe洛必达6.【答案】0【解析】220001112limlimlim0coscossinxxxxxxxxxexexex等价替换洛必达7.【答案】1【解析】ln11111lnlimlimlim=1lnlnlnxxxxxxxexxxxxxxx对数恒等变形等价替换8.【答案】12【解析】002001cos1+cos1coslim=lim1cos1cos1+cos111cos112=limlim12221cos2xxxxxxxxxxxxxxxxxx等价替换9.【答案】12【解析】201tan1sinlimln1xxxxxx0tansinlim2(ln1)xxxxxx00tan(1cos)(1cos)limlim2(ln1)2(ln1)xxxxxxxxxxxx011coslim2ln1xxxx2012lim2ln1xxxx00111limlim2(1)21xxxxxx洛=1210.【答案】32e【解析】coscos1332200(1)limlim1111xxxxeeeexx200221(1cos)32limlim11233xxexexexx【解析】2222222243000023222000011sinsin2sincos2limlimlimlimsinsin412sin222cos221cos21112limlim=lim=lim.412663xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx洛必达洛必达