学号：PB07203143姓名：王一飞院（系）：物理系物质对β射线的吸收【数据处理】1.铝片厚度的计算N12345平均不确定度厚片(cm2)31.200032.314030.318631.694030.673531.24000.3558薄片(cm2)29.148529.682030.380029.028029.550029.55770.2387由上表可以看出，铝片的面积的不确定度较大，所以相差较大，这将是导致实验误差的主要原因之一。厚铝片质量为3550mgd1=m厚S厚=3550mg31.2400cm2≈113.64mg⋅cm−2薄铝片质量为558mgd2=m薄S薄=558mg29.5577cm2≈18.88mg⋅cm−22.计数管坪曲线计数时间为10s，得到结果见下表:工作电压和计数结果数据工作电压/11.1v122122.2124.1126.2128.1130.3132.3134.2136.3工作电压/v1354.21356.421377.511400.821421.911446.331468.531489.621512.93计数结果N0943122334735083387359636583669E=1/(N)1/20.0180.0170.0170.0170.0170.0170.017NE=(N)1/255.8757.8559.2358.2059.9760.4860.57工作电压/11.1v138.1140.1142.1144.3146.3148.3150.2152.2工作电压/v1532.911555.111577.311601.731623.931646.131667.221689.42计数结果36733766365437443863380538973958E=1/(N)1/20.0170.0160.0170.0160.0160.0160.0160.016NE=(N)1/260.6061.3760.4561.1962.1561.6862.4262.91由此作出曲线图如下:取点(1400.82,3347)和点(1667.22,3897)为计算用点,得结果如下:工作电压:V=V1+V22=1400.82+1667.222=1534.02V坪长:V2−V1=1667.22−1400.82=266.40V坪斜率为:T=N2−N1N1(V2−V1)×100%=0.06%由于T<0.1%/v,故该结果可用3.吸收曲线的绘制本底计数为：300s114个，10s3.8个吸收曲线测量数据薄片个数厚片个数质量厚度mg/cm2时间/s计数10s计数(减本底)误差E误差个数NI/I0I/I0误差000.001036733669.20.016560.571.00000.01651018.881032723268.20.017557.170.89070.01562037.761029072903.20.018653.880.79120.01473056.641025922588.20.019750.870.70540.01394075.521023762372.20.020548.710.64650.01335094.401021422138.20.021646.240.58270.012601113.641019601956.20.022644.230.53310.012111132.521018261822.20.023442.690.49660.011621151.41017801776.20.023742.140.48410.011531170.281015371533.20.025539.160.41790.010741189.161013721368.20.027036.990.37290.010151208.041012831279.20.028035.770.34860.009802227.281011861182.20.029134.380.32220.009422265.0410999995.20.031731.550.27120.008642302.810810806.20.035228.3...
