第1页共1页天津大学化工原理826模拟试题(三)答案一.选择与填空(20%)1.c2.真空表,压力表,调节阀,压力表,出口阀,流量3.2Δp112222121222kkvAkvAkddv4.金属,气体5.d6.b7.b二.(13%)解:如图,作1-1、2-2截面,取1-1为零截面。在1--1与2--2(管外侧)间列柏努利方程:gz1+u12/2+p1/+We=gz2+u22/2+p2/+hfz1=0,z2=22m,u10,u2=0,p1(表)=0p2=0.85at=0.859.81104=8.34104Pa管内流速u=VA=42.5/(40.123600)=1.50m/sWe=gz2+p2/+hf即321.5=9.8122+8.34104/103+hfhf=22.28J/kghf=lledu2/2=11001.1.502/2=22.28=0.0180答:摩擦系数λ值为0.0180。三.(6%)解:依题意知,往复泵流量为20L/s,离心泵单独操作的性能为:He=60.6-0.00156qv2离心泵单独操作时的工作点:He=He',qv=51.6L/s即60.6-0.00156×51.62=45+K×51.62∴K=0.0043m/(L/s)2答:管路特性方程He'=H0+Kqv2中的K值为0.0043m/(L/s)211221上研途进组织找大牛微信公众号:yentocn官方微博:研途网第2页共1页四.(12%)解:(1)Q=V/(τ+τD+τW)∴Q=2.5/(15/60+τD+τW)5分∴τD+τW=0.375hr=22.5min(2)V2=KA2τ∴2.52=K×102×0.255分∴K=0.25m2/hK'/K=ΔP'/ΔP∴K'=1.5/2.5×0.25=0.15m2/hr(V')2=K'A2τ'∴(V')2=0.15×102×0.25V'=1.936m3Q'=1.936/(0.25+0.375)=3.90m3/hr五.(13%)解:(1)溶液放热Q=W1cp1(T1-T2)=1.4×2×103×(150-100)=1.4×105W1/Ko=do/(αidi)+1/αo=0.025/(1160×0.02)+1/930=2.15×10-3Ko=464W/m2℃冷却水用量W2=Q/[Cp2(t2-t1)]=1.4×105/[4180(60-25)]=0.957Kg/s=3445Kg/h(2)△tm=[(150-60)-(100-25)]/ln[(150-60)/(100-25)]=82.3℃Ao=Q/(Ko△tm)=1.4×105/(464×82.3)=3.67ml=Ao/(πdo)=3.67/(π×0.025)=46.7m六.(11%)解:MM=46*0.2+18*0.8=23.6F=100kmol/hF=D+WFXF=DXD+WXWW=80kmol/hD=20kmol/h0.6=R*0.5/(R+1)+0.8/(R+1)R=2七.(10%)解:X1=0.667kg水/kg绝干料X2=0.053kg水/kg绝干料GC=G1(1-w1)=600kg绝干料/hW=GC(X1-X2)=368.4kg水/hL=W/(H1-H2)=12280kg绝干气/hL’=L(1+H1)=12390.5kg/hG2=G1-W=631.6kg/h八.实验部分(15%)2上研途进组织找大牛微信公众号:yentocn官方微博:研途网