一、选择题1.lg8+3lg5的值为()A.-3B.-1C.1D.3解析:lg8+3lg5=3lg2+3lg5=3(lg2+lg5)=3lg10=3.答案:D2.若log34·log8m=log416,则m等于()A.3B.9C.18D.27解析:原式可化为:log8m=∴log2m=2log43,∴m=3.m=27.答案:D3.已知a=log32,用a来表示log38-2log36()A.a-2B.5a-2C.3a-(1+a)2D.3a-a2-1解析:log38-2log36=3log32-2(log32+log33)=3a-2(a+1)=a-2.答案:A4.已知方程x2+xlog26+log23=0的两根为α、β,则()α·()β=()A.B.36C.-6D.6解析:由题意知:α+β=-log26,()α·()β=()α+β=()-log26=4log26=22log26=36.答案:B二、填空题5.2(lg)2+lg·lg5+=________.解析:原式=2(lg)2+lg·lg5+1-lg=2(lg)2+lg(lg5-1)+1=2(lg)2-2(lg)2+1=1.答案:16.设g(x)=,则g(g())=________.解析:∵>0,∴g()=ln.而g(g())=g(ln)=e=.答案:7.方程log3(x-1)=log9(x+5)的解是________.解析:由题意知解之得x=4.答案:x=48.已知x3=3,则3log3x-logx23=________.解析:3log3x=log3x3=log33=1,而logx23=logx33=log33=,∴3log3x-logx23=1-=-.答案:-三、解答题9.计算下列各式的值:(1);(2)lg2+lg50+31-log92;(3)2+()+lg20-lg2-(log32)·(log23)+(-1)lg1.解:(1)原式===.(2)原式=lg2+lg+3×3=lg2+(2-lg2)+3×3-log32=2+3×3=2+3×2-=2+.(3)原式=+[()2]-+lg-·+1=+()-1+lg10-1+1=2.10.设3x=4y=36,求+的值.解:由已知分别求出x和y,∵3x=36,4y=36,∴x=log336,y=log436,由换底公式得:x==,y==,∴=log363,=log364,∴+=2log363+log364=log36(32×4)=log3636=1.