课后作业(四十九)复习巩固一、选择题1.在△ABC中,A=,cosB=,则sinC等于()A.B.-C.D.-[解析] cosB=,∴B为锐角∴sinB==.又 sinC=sin[π-(A+B)]=sin(A+B)=sincosB+cossinB=×+×==[答案]A2.计算cos(80°+2α)cos(65°+2α)+sin(80°+2α)sin(65°+2α)的值为()A.B.C.D.[解析]原式=cos[(80°+2α)-(65°+2α)]=cos15°=cos(45°-30°)=.[答案]C3.sin15°-cos15°的值为()A.B.-C.D.-[解析]原式=sin30°·sin15°-cos30°·cos15°=-(cos30°·cos15°-sin30°·sin15°)=-cos(30°+15°)=-cos45°=-.[答案]B4.已知sinα=,cos(α+β)=-,且α,β∈,则sinβ等于()A.-B.C.-D.[解析]因为sinα=,cos(α+β)=-,且α,β∈,所以cosα=,sin(α+...