2022考研数学全程班作业答案——《高分强化521》新浪微博@考研数学周洋鑫12022考研数学全程班作业答案——《高分强化521》作业2第2章线代·矩阵2.1矩阵运算【1】设n维向量()T,0,,0,,0aaa=,E为n阶单位矩阵,矩阵T=−AE,T1a=+BE,又B是A的逆矩阵,则a=.解析:()TT1aABEE=−+TTTT11=aaE+−−TTT111aa=E+−−,又T222002aaa=++++=,T112aa=EE+−−=,所以T112O−−=aa,又是非零列向量,所以TO.故1120−−=aa,解得1a=−或102=a(不符合题干条件,舍去).【2】设3113=−A,求32A和33A.解析:231311001313010==−−A,所以()16161632216100100010010===AA,16333216163131100101313010===−−AAA.【3】设1010100,001−−==−ABPAP,其中P为三阶可逆矩阵,则200422−=BA.一笑而过考研数学2022考研数学全程班作业答案——《高分强化521》新浪微博@考研数学周洋鑫2解析:200412004−=BPAP,2010010100100100010001001001−−−==−−−A,所以()1002100220042100100010010001001−==−==AAE,所以200421100100300220102010030001001001−−−−=−−=−−=−BAPEPE.【4】设100100=A,求6A.解析:100100100100000==+AE,记010001000=B()666660=kkkkCAEBB−==+,65465426560006000156150000600000000000EBB=++=++6546566150600=.【5】设=APP,其中1111102,11115−=−=−P,求()()8256=−+AAEAA.解析:60=−P,所以P可逆,=APP,右乘1−P得1−=APP,所以()()8281911015656−−−=−+=−+AAEAAPPPPPP()8910156−=−+PP11111210201110−=−−P1114111111=...