能力升级练(五)三角函数的图象与性质一、选择题1.sin600°的值为()A.-12B.-❑√32C.12D.❑√32解析sin600°=sin(360°+240°)=sin240°=sin(180°+60°)=-sin60°=-❑√32.答案B2.已知角θ的顶点与原点重合,始边与x轴的正半轴重合,终边在直线y=2x上,则cos2θ=()A.-45B.-35C.35D.45解析由题意知,tanθ=2,即sinθ=2cosθ.将其代入sin2θ+cos2θ=1中可得cos2θ=15,故cos2θ=2cos2θ-1=-35.答案B3.(2023山东潍坊一模)若角α的终边过点A(2,1),则sin(32π-α)=()A.-2❑√55B.-❑√55C.❑√55D.2❑√55解析由三角函数定义,cosα=2❑√5=25❑√5,1则sin(32π-α)=-cosα=-2❑√55.答案A4.若tanθ=-13,则cos2θ=()A.-45B.-15C.15D.45解析cos2θ=cos2θ-sin2θ=cos2θ-sin2θcos2θ+sin2θ=1-tan2θ1+tan2θ=45.答案D5.(2023...